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Friday, March 5, 2010

Squaring a 2-digit number ending in 8

  1. Choose a 2-digit number ending in 8.
  2. The last digit of the answer is always 4: _ _ _ 4
  3. Multiply the first digit by 6 and add 6 (keep the
    carry): _ _ X _
  4. Multiply the first digit by the next consecutive
    number and add the carry: the product is the first
    two digits: XX _ _.

Example:

  1. If the number is 78:
  2. The last digit of the answer is 4: _ _ _ 4
  3. Multiply the first digit (7) by 6 and add 6 (keep the
    carry): 7 × 6 = 42, 42 + 6 = 48; the next digit of the
    answer is 8 (keep carry 4): _ _ 8 4
  4. Multiply the first digit (7) by the next number (8)
    and add the carry (4):
    7 × 8 = 56, 56 + 4 = 60 (the first two digits): 6 0 _ _
  5. So 78 × 78 = 6084.

See the pattern?

  1. For 38 × 38
  2. The last digit of the answer is 4: _ _ _ 4
  3. Multiply the first digit (3) by 6 and add 6 (keep the
    carry): 3 × 6 = 18, 18 + 6 = 24; the next digit of the
    answer is 4 (keep carry 2): _ _ 4 4
  4. Multiply the first digit (3) by the next number (4)
    and add the carry (2):
    3 × 4 = 12, 12 + 2 = 14 (the first two digits): 1 4 _ _
  5. So 38 × 38 = 1444

Learn the pattern, practice other examples, and you will be a whiz at giving these squares.

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